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0=-x^2+3x-0.6865
We move all terms to the left:
0-(-x^2+3x-0.6865)=0
We add all the numbers together, and all the variables
-(-x^2+3x-0.6865)=0
We get rid of parentheses
x^2-3x+0.6865=0
a = 1; b = -3; c = +0.6865;
Δ = b2-4ac
Δ = -32-4·1·0.6865
Δ = 6.254
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{6.254}}{2*1}=\frac{3-\sqrt{6.254}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{6.254}}{2*1}=\frac{3+\sqrt{6.254}}{2} $
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